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X^2+2X-15=60
We move all terms to the left:
X^2+2X-15-(60)=0
We add all the numbers together, and all the variables
X^2+2X-75=0
a = 1; b = 2; c = -75;
Δ = b2-4ac
Δ = 22-4·1·(-75)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{19}}{2*1}=\frac{-2-4\sqrt{19}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{19}}{2*1}=\frac{-2+4\sqrt{19}}{2} $
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